Question #1100097

Finding the work done by this force from t =0 s to t =2.84 s?

A single constant force acts in the +x direction on an 2.06 kg object that is constrained to move along the x axis. As a result the object's position as a function of time is: x(t) = A + Bt^2 + Ct^4 A = 1.38 m B = 3.82 m/s^2 C = 0.303 m/s^4 How much work is done by this force from t = 0 s to t = 2.84 s?

2012-10-19 19:25:34

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