Question #11700093

# How do I use the half-angle formula?

**I'm given a triangle in quadrant 1, adjacent side is 24, opposite side is 10, and I am asked to find sin (theta/2)
I've found the hypothenuse of 26, plugged it into the half-angle formula, and obtained a wrong answer. I current have .445 but I don't know what I am doing wrong. Would anyone care to explain?
**

TELL US , if you have any answer

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