Question #7750205

# Finding the solution for y''-y=xe^x with the initial conditions f(0)=1, f'(0)=-1?

**I have got the the solution y=Ae^x+Be^-x+(x^2 * e^x)/4+(x * e^x)/4 but how do I apply the initial conditions?
Thank you very much for your help!
**

TELL US , if you have any answer

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