Question #7750205
Finding the solution for y''-y=xe^x with the initial conditions f(0)=1, f'(0)=-1?
I have got the the solution y=Ae^x+Be^-x+(x^2 * e^x)/4+(x * e^x)/4 but how do I apply the initial conditions? Thank you very much for your help!
TELL US , if you have any answer
Sponsored ads