Question #7750205

Finding the solution for y''-y=xe^x with the initial conditions f(0)=1, f'(0)=-1?

I have got the the solution y=Ae^x+Be^-x+(x^2 * e^x)/4+(x * e^x)/4 but how do I apply the initial conditions? Thank you very much for your help!

2013-06-24 16:07:49

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